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-0.5x^2+2x+2=0.875x+0.875
We move all terms to the left:
-0.5x^2+2x+2-(0.875x+0.875)=0
We get rid of parentheses
-0.5x^2+2x-0.875x-0.875+2=0
We add all the numbers together, and all the variables
-0.5x^2+1.125x+1.125=0
a = -0.5; b = 1.125; c = +1.125;
Δ = b2-4ac
Δ = 1.1252-4·(-0.5)·1.125
Δ = 3.515625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.125)-\sqrt{3.515625}}{2*-0.5}=\frac{-1.125-\sqrt{3.515625}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.125)+\sqrt{3.515625}}{2*-0.5}=\frac{-1.125+\sqrt{3.515625}}{-1} $
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